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author | Jeff King <peff@peff.net> | 2012-07-23 14:48:57 -0400 |
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committer | Junio C Hamano <gitster@pobox.com> | 2012-07-23 13:10:43 -0700 |
commit | 447b99c8b1102746054644acd268f4c1b115a9f8 (patch) | |
tree | 8a8eedaa50f8ccaf477d0341648dd0b8465a6bb1 | |
parent | Git 1.7.9.7 (diff) | |
download | tgif-447b99c8b1102746054644acd268f4c1b115a9f8.tar.xz |
advice: pass varargs to strbuf_vaddf, not strbuf_addf
The advise() function takes a variable number of arguments
and converts them into a va_list object to pass to strbuf
for handling. However, we accidentally called strbuf_addf
(that takes a variable number of arguments) instead of
strbuf_vaddf (that takes a va_list).
This bug dates back to v1.7.8.1-1-g23cb5bf, but we never
noticed because none of the current callers passes a string
with a format specifier in it. And the compiler did not
notice because the format string is not available at
compile time.
Signed-off-by: Jeff King <peff@peff.net>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
-rw-r--r-- | advice.c | 2 |
1 files changed, 1 insertions, 1 deletions
@@ -26,7 +26,7 @@ void advise(const char *advice, ...) const char *cp, *np; va_start(params, advice); - strbuf_addf(&buf, advice, params); + strbuf_vaddf(&buf, advice, params); va_end(params); for (cp = buf.buf; *cp; cp = np) { |